{VERSION 5 0 "SUN SPARC SOLARIS" "5.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 1 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 1 }{CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 257 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{PSTYLE "Normal " -1 0 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Heading 1" 0 3 1 {CSTYLE "" -1 -1 "" 1 18 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }1 0 0 0 8 4 0 0 0 0 0 0 -1 0 } {PSTYLE "Heading 2" 3 4 1 {CSTYLE "" -1 -1 "" 1 14 0 0 0 0 0 0 0 0 0 0 0 0 0 0 }0 0 0 -1 8 2 0 0 0 0 0 0 -1 0 }{PSTYLE "Heading 3" 4 5 1 {CSTYLE "" -1 -1 "" 1 12 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }0 0 0 -1 0 0 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Output" 0 11 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 }3 3 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Plot" 0 13 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 }3 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "" 0 256 1 {CSTYLE "" -1 -1 "" 1 24 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "" 0 258 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 }3 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }} {SECT 0 {PARA 256 "" 0 "" {TEXT -1 13 "Assingment 2 " }{TEXT 257 9 "So lutions" }}{SECT 0 {PARA 3 "" 0 "" {TEXT -1 23 "Q.1. Consider the curv e" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 45 "x(t):= t*sin(t); y(t):= t*cos(t); 0<=t, t<=Pi;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>-%\"xG6#%\" tG*&F'\"\"\"-%$sinGF&F)" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>-%\"yG6#% \"tG*&F'\"\"\"-%$cosGF&F)" }}{PARA 11 "" 1 "" {XPPMATH 20 "6$1\"\"!%\" tG1F%%#PiG" }}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 18 "a) Graph the curve " }}{SECT 1 {PARA 5 "" 0 "" {TEXT -1 16 "Solution/Answwer" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 27 "plot([x(t),y(t), t=0..Pi]);" }} {PARA 0 "> " 0 "" {MPLTEXT 1 0 50 "inital_point, P1 = (0,0); end_point , P2 = (0,-Pi);" }}{PARA 13 "" 1 "" {GLPLOT2D 157 301 301 {PLOTDATA 2 "6%-%'CURVESG6$7W7$$\"\"!F)F(7$$\"3ItC!fNUbo%!#?$\"3!f&f3#*)G<$o!#>7$$ \"3RWQu4fXN;F0$\"3KnySQJ6q7!#=7$$\"3![`U7T+5y$F0$\"31m#3I@oO\">F67$$\" 3IJv+#)\\i7oF0$\"3\")*f(4_&H_`#F67$$\"3\"*RKQ!f&4n5F6$\"3-5)e>(\\(*=JF 67$$\"3qXTcM&Hn\\\"F6$\"3'4t;sQjGs%F6$\"38j,j)pXsS&F67$$ \"3G(e%G&>ttb&F6$\"3N>i3Re0abF67$$\"3\\\"yB)o;%\\V'F6$\"3mfz8i<^5cF67$ $\"3/s6atY45tF6$\"3[%e!4\"!#<$\"3S%4r2TX#*\\%F67$$\"3-5v;$z;V<\"F_q$\"3Av&**p# Qu#>F6OLCF-7$$\"3coIKzZvM;F_q$ !3vUmbGFk36F67$$\"3?`4pG\\!\\o\"F_q$!3$HM8ZIq'o@F67$$\"3k-=F_q$!38g $4cpb$H!*F67$$\"3;q@2*e,P\"=F_q$!3#*)fvJ;kv%z\"F_q$ !3tT1C))y\"o?\"F_q7$$\"3!Q(=0![Qgw\"F_q$!3jN>Q-n:_8F_q7$$\"35:i\"pU[pUbDQ;:F_q$!3a$\\))y&e=p>F_q7$$\"36 6A,moN<9F_q$!3,B(e>CaM7#F_q7$$\"3'RJF<3g'38F_q$!30F.l(pjwE#F_q7$$\"3e1 w!e8gT=\"F_q$!37V?h%ej&4CF_q7$$\"3f$4YRaNw/\"F_q$!3^C/J=`fVDF_q7$$\"3 \"*yACf@G5\"*F6$!3:2$Ql[C*fEF_q7$$\"3*y=8k94yT(F6$!3>w7&yS!3%y#F_q7$$ \"3+_W$ziI'=mF6$!3q=PbH97OGF_q7$$\"3)o#)y`s!=%z&F6$!3HNNjve&e)GF_q7$$ \"3;#=j\\Uk!))[F6$!3#[*4@f>AOHF_q7$$\"3,6RY<#[[&RF6$!3;\\)e$Gpr$)HF_q7 $$\"3roBZ-v5PIF6$!3Y$3n'[:PEIF_q7$$\"3C6*)4^UB'4#F6$!3Fixh+_ " 0 "" {MPLTEXT 1 0 11 "t0 := Pi/2;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#t0G,$*&\"\"#!\"\"%#PiG\"\"\"F*" }}}{SECT 1 {PARA 5 "" 0 "" {TEXT -1 8 "Solution" }}{EXCHG {PARA 0 "" 0 "" {TEXT -1 64 "The equati on of the tangent line at the given point is given by " }}{PARA 258 " " 0 "" {TEXT -1 17 "y-y0 = m(x-x0) , " }}{PARA 0 "" 0 "" {TEXT -1 6 "w here " }}{PARA 0 "" 0 "" {TEXT -1 34 " m = dy/dx (t0) \+ " }}{PARA 0 "" 0 "" {TEXT -1 20 " y0 = y(t0)" }}{PARA 0 "" 0 "" {TEXT -1 20 " x0 = x(t0)" }}{PARA 0 "" 0 "" {TEXT -1 1 " " }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 32 "First, find the derivative dy/dx" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 56 "dx/dt=Diff(x(t),t);dx/dt=diff(x(t),t);dxt:=diff(x(t), t):" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/*&%#dxG\"\"\"%#dtG!\"\"-%%Diff G6$*&%\"tGF&-%$sinG6#F-F&F-" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/*&%#dx G\"\"\"%#dtG!\"\",&-%$sinG6#%\"tGF&*&F-F&-%$cosGF,F&F&" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 57 "dy/dt=Diff(y(t),t);dy/dt=diff(y(t), t); dyt:=diff(y(t),t):" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/*&%#dyG\"\" \"%#dtG!\"\"-%%DiffG6$*&%\"tGF&-%$cosG6#F-F&F-" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/*&%#dyG\"\"\"%#dtG!\"\",&-%$cosG6#%\"tGF&*&F-F&-%$sinG F,F&F(" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 40 "dy/dx = Diff('y(t )', t)/Diff('x(t)', t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/*&%#dyG\" \"\"%#dxG!\"\"*&-%%DiffG6$-%\"yG6#%\"tGF0F&-F+6$-%\"xGF/F0F(" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 14 "dy/dx=dyt/dxt;" }}{PARA 11 " " 1 "" {XPPMATH 20 "6#/*&%#dyG\"\"\"%#dxG!\"\"*&,&-%$cosG6#%\"tGF&*&F. F&-%$sinGF-F&F(F&,&F0F&*&F.F&F+F&F&F(" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 37 "Second, use the derivative to find m:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 24 "m = subs(t=t0, dyt/dxt);" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 25 "m := eval(dyt/dxt, t=t0);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%\"mG*&,&-%$cosG6#,$*&\"\"#!\"\"%#PiG\"\"\"F/F/*&#F/F, F/*&F.F/-%$sinGF)F/F/F-F/,&F3F/*&#F/F,F/*&F.F/F'F/F/F/F-" }}{PARA 11 " " 1 "" {XPPMATH 20 "6#>%\"mG,$*&\"\"#!\"\"%#PiG\"\"\"F(" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 32 "Third, evaluate y(t0) and x(t0):" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 43 "y0=subs(t=t0, y(t));y0 := ev al(y(t), t=t0);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%#y0G,$*&#\"\"\"\" \"#F(*&%#PiGF(-%$cosG6#,$*&F)!\"\"F+F(F(F(F(F(" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#y0G\"\"!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 42 "x0=subs(t=t0, x(t)); x0:=eval(x(t), t=t0);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%#x0G,$*&#\"\"\"\"\"#F(*&%#PiGF(-%$sinG6#,$*&F)!\"\"F+ F(F(F(F(F(" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#x0G,$*&\"\"#!\"\"%#Pi G\"\"\"F*" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 10 "Therefore " }}}} {SECT 1 {PARA 5 "" 0 "" {TEXT -1 6 "Answer" }}{EXCHG {PARA 0 "" 0 "" {TEXT -1 36 "The equation of the tangent line is:" }}}{EXCHG {PARA 0 " > " 0 "" {MPLTEXT 1 0 16 "y-y0 = m*(x-x0);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%\"yG,$*(\"\"#!\"\"%#PiG\"\"\",&%\"xGF**&F'F(F)F*F(F*F (" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 3 "or " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 24 "y-y0 = expand(m*(x-x0));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%\"yG,&*&#\"\"\"\"\"#F(*&%#PiGF(%\"xGF(F(!\"\"*&#F(\" \"%F(*$)F+F)F(F(F(" }}}}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 96 "c) Set u p the integral representing the surface area when revolving the curve \+ around the y-axis " }}{SECT 1 {PARA 5 "" 0 "" {TEXT -1 15 "Solution/An swer" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 66 "SA=2*Pi*Int(x(t)*sqr t((Diff(x(t),t))^2+(Diff(y(t),t))^2),t=0..Pi);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%#SAG,$*(\"\"#\"\"\"%#PiGF(-%$IntG6$*(%\"tGF(-%$sinG6# F.F(,&*$)-%%DiffG6$*&F.F(F/F(F.F'F(F(*$)-F66$*&F.F(-%$cosGF1F(F.F'F(F( #F(F'/F.;\"\"!F)F(F(" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 66 "SA= 2*Pi*int(x(t)*sqrt((diff(x(t),t))^2+(diff(y(t),t))^2),t=0..Pi);" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#/%#SAG,$*(\"\"#\"\"\"%#PiGF(-%$intG6$* (%\"tGF(-%$sinG6#F.F(,&*$),&F/F(*&F.F(-%$cosGF1F(F(F'F(F(*$),&F7F(*&F. F(F/F(!\"\"F'F(F(#F(F'/F.;\"\"!F)F(F(" }}}}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 36 "d) Evaluate the integral found in c)" }}{SECT 1 {PARA 5 " " 0 "" {TEXT -1 8 "Solution" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "SA = expand(rhs(%));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%#SAG,$*( \"\"#\"\"\"%#PiGF(-%$intG6$*(%\"tGF(-%$sinG6#F.F(,**$)F/F'F(F(*&)F.F'F ()-%$cosGF1F'F(F(*$F7F(F(*&F6F(F4F(F(#F(F'/F.;\"\"!F)F(F(" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "simplify(%);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%#SAG,$*(\"\"#\"\"\"%#PiGF(-%$intG6$*(%\"tGF(-%$sinG6# F.F(,&*$)F.F'F(F(F(F(#F(F'/F.;\"\"!F)F(F(" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 21 "Evaluate the integral" }}}}{SECT 1 {PARA 5 "" 0 "" {TEXT -1 6 "Answer" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "SA = evalf(r hs(%));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%#SAG$\"+I'\\AB%!\")" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 83 "The surface area of the solid obta ined by revolving the curve around the y-axis is " }}{PARA 0 "" 0 "" {TEXT -1 23 "SA = 42.32 units sqared" }}}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 73 "_________________________________________________________ ________________" }}}}{SECT 0 {PARA 3 "" 0 "" {TEXT -1 24 "Q.2. 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>&**\\\"F9$\"3rF5o?!)*z[\"F97$$!3+(oNtP^u[\"F9$\"37uo\"fy!Q18F97$$!3rm I&yaTIX\"F9$\"3S46USahF6F97$$!3)es=JqFtQ\"F9$\"3yiq)H\"3I'H*F-7$$!3_P \\V3?y%H\"F9$\"3y!zgkfgnU(F-7$$!3S]o^p'G2>\"F9$\"3>3Wn')3pxeF-7$$!3D6_ )RTY#o5F9$\"3*=4]RA2)pWF-7$$!3#eZ3'eG%\\>*F-$\"37whTg?r[JF-7$$!3mFqvD= nXvF-$\"3FF7b^[4O?F-7$$!3yflqaMPUeF-$\"3nB\"*p.&\\X=\"F-7$$!3\"pFqjx7 \\/%F-$\"3[^G?DgpcbF07$$!3![uGq%4XT?F-$\"3KTzwVpm&R\"F07$$\"3ttR=U6ChC Ff[m$\"3[!pfm)fB>?Fi[m-F[\\m6&F]\\mF(F^\\mF(-%%VIEWG6$%(DEFAULTGFijn" 1 2 0 1 10 0 2 9 1 4 2 1.000000 45.000000 45.000000 0 0 "Curve 1" "Cur ve 2" }}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 18 "r1 is the circle, " }} {PARA 0 "" 0 "" {TEXT -1 22 "r2 is the 4 leaf rose." }}{PARA 0 "" 0 " " {TEXT -1 88 "They both start and end at (0,0) but the circle is trac ed twice over the given interval." }}}}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 81 "b) Find the polar coordinates of all the points of intersection of the two curves" }}{SECT 1 {PARA 5 "" 0 "" {TEXT -1 8 "Solution" }} {EXCHG {PARA 0 "" 0 "" {TEXT -1 22 "First, find the angles" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "'r2'='r1';" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%#r2G%#r1G" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "'r2-r1'=0;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/,&%#r2G\"\"\"%#r1G! \"\"\"\"!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "r2-r1=0;" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#/,&*&\"\"$\"\"\"-%$sinG6#,$*&\"\"#F'%& thetaGF'F'F'F'*&F&F'-F)6#F.F'!\"\"\"\"!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "expand(%);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/,&*(\" \"'\"\"\"-%$sinG6#%&thetaGF'-%$cosGF*F'F'*&\"\"$F'F(F'!\"\"\"\"!" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "factor(%);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/,$*(\"\"$\"\"\"-%$sinG6#%&thetaGF',&*&\"\"#F'-%$cos GF*F'F'F'!\"\"F'F'\"\"!" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 29 " sin(theta)=0, cos(theta)=1/2;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6$/-%$s inG6#%&thetaG\"\"!/-%$cosGF&#\"\"\"\"\"#" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 28 "Theta=\{solve(r2=r1, theta)\};" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%&ThetaG<&\"\"!%#PiG,$*&\"\"$!\"\"F'\"\"\"F,,$*&F*F+F' F,F+" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 70 "Note 1: -Pi/3 is not in \+ the domain, so we need to shift it up by 2Pi:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 17 "theta=-Pi/3+2*Pi;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%&thetaG,$*(\"\"&\"\"\"\"\"$!\"\"%#PiGF(F(" }}}{EXCHG {PARA 0 " " 0 "" {TEXT -1 114 "Note 2: For this angle the radius is negative so \+ we can represent it alternatively as an angle in the II quadrant " }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 17 "theta= 5/3*Pi-Pi;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%&thetaG,$*(\"\"#\"\"\"\"\"$!\"\"%#PiGF(F( " }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 22 "Second, find the radii" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 47 "'r1'=eval(r1, theta=0), eval (r2, theta=0)='r2';" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 53 "'r1'=eval(r1 , theta=Pi/3), eval(r2, theta=Pi/3)='r2';" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 49 "'r1'=eval(r1, theta=Pi), eval(r2, theta=Pi)='r2';" }} {PARA 0 "> " 0 "" {MPLTEXT 1 0 57 "'r1'=eval(r1, theta=5/3*Pi), eval(r 2, theta=5/3*Pi)='r2';" }}{PARA 11 "" 1 "" {XPPMATH 20 "6$/%#r1G\"\"!/ F%%#r2G" }}{PARA 11 "" 1 "" {XPPMATH 20 "6$/%#r1G,$*(\"\"$\"\"\"\"\"#! \"\"F'#F(F)F(/F%%#r2G" }}{PARA 11 "" 1 "" {XPPMATH 20 "6$/%#r1G\"\"!/F %%#r2G" }}{PARA 11 "" 1 "" {XPPMATH 20 "6$/%#r1G,$*(\"\"$\"\"\"\"\"#! \"\"F'#F(F)F*/F%%#r2G" }}}}{SECT 1 {PARA 5 "" 0 "" {TEXT -1 6 "Answer " }}{EXCHG {PARA 0 "" 0 "" {TEXT -1 60 "The polar coordinates of all t he points of intersection are:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 160 "P1(eval(r1, theta=0), 0); P2(eval(r1, theta=Pi/3), Pi/3);P3=( eval(r1, theta=5/3*Pi), 5/3*Pi), P3 = (eval(r1, theta=2/3*Pi), 2/3*Pi) ;P4=(eval(r1, theta=Pi), Pi);" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" } }{PARA 11 "" 1 "" {XPPMATH 20 "6#-%#P1G6$\"\"!F&" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#-%#P2G6$,$*(\"\"$\"\"\"\"\"#!\"\"F(#F)F*F),$*&F(F+%#PiG F)F)" }}{PARA 11 "" 1 "" {XPPMATH 20 "6$/%#P3G6$,$*(\"\"$\"\"\"\"\"#! \"\"F(#F)F*F+,$*(\"\"&F)F(F+%#PiGF)F)/F$6$,$*(F(F)F*F+F(F,F),$*(F*F)F( F+F0F)F)" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/%#P4G6$\"\"!%#PiG" }}}}} {SECT 1 {PARA 4 "" 0 "" {TEXT -1 79 "c) Set up an integral representin g the area of the region common to both curves" }}{SECT 1 {PARA 5 "" 0 "" {TEXT -1 8 "Solution" }}{EXCHG {PARA 0 "" 0 "" {TEXT -1 95 "Note1 : Since the area is symmetric we can calculate just the common area in the first quadrant " }}{PARA 0 "" 0 "" {TEXT -1 42 "and then double i t to find the total area." }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 115 "Not e2: The common area is that under the circle in (0, Pi/3) and under th e rose in (Pi/3, Pi/2), as depicted below:" }}}{EXCHG {PARA 0 "> " 0 " " {MPLTEXT 1 0 133 "plot(\{[r2, theta, theta=0..Pi/2],[r1 ,theta, thet a=0..Pi/2], [r, Pi/3, r=0..3*sqrt(3)/2]\}, coords=polar, colour=[green , green, red]);" }}{PARA 13 "" 1 "" {GLPLOT2D 220 326 326 {PLOTDATA 2 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}}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 9 "Ther efore" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 66 "Half_A:=1/2*(Int(r 1^2, theta=0..Pi/3)+Int(r2^2,theta=Pi/3..Pi/2));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%'Half_AG,&*&#\"\"\"\"\"#F(-%$IntG6$,$*&\"\"*F()-%$sin G6#%&thetaGF)F(F(/F4;\"\"!,$*&\"\"$!\"\"%#PiGF(F(F(F(*&F'F(-F+6$,$*&F/ F()-F26#,$*&F)F(F4F(F(F)F(F(/F4;F8,$*&F)F;F " 0 "" {MPLTEXT 1 0 13 "A:= 2*Half_ A;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"AG,&-%$IntG6$,$*&\"\"*\"\"\" )-%$sinG6#%&thetaG\"\"#F,F,/F1;\"\"!,$*&\"\"$!\"\"%#PiGF,F,F,-F'6$,$*& F+F,)-F/6#,$*&F2F,F1F,F,F2F,F,/F1;F6,$*&F2F9F:F,F,F," }}}}}{SECT 1 {PARA 4 "" 0 "" {TEXT -1 36 "d) Evaluate the integral found in c)" }} {SECT 1 {PARA 5 "" 0 "" {TEXT -1 8 "Solution" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 56 "A=(int(r1^2, theta=0..Pi/3)+int(r2^2,theta=Pi/3..P i/2));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/,&-%$IntG6$,$*&\"\"*\"\"\") -%$sinG6#%&thetaG\"\"#F+F+/F0;\"\"!,$*&\"\"$!\"\"%#PiGF+F+F+-F&6$,$*&F *F+)-F.6#,$*&F1F+F0F+F+F1F+F+/F0;F5,$*&F1F8F9F+F+F+,&*(\"#FF+\"#;F8F7# F+F1F8*(F*F+\"\"%F8F9F+F+" }}}}{SECT 1 {PARA 5 "" 0 "" {TEXT -1 6 "Ans wer" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 13 "'A'=evalf(A);" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#/%\"AG$\"+LxuXT!\"*" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 57 "The common area to both curves is A = 4.15 uni ts squared" }}}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 73 "_________________ ________________________________________________________" }}}}}{MARK " 1" 0 }{VIEWOPTS 1 1 0 1 1 1803 1 1 1 1 }{PAGENUMBERS 0 1 2 33 1 1 }